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Go Back   Talkgold HYIP, Investment & Money Forum > Caution : Risky High Yield Investing Programs > Cash Folder - Make Money for Being at Talkgold
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  #1  
Old 11-30-2008, 05:09 AM
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mrGSH mrGSH is offline
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Default $3 easy logical question.

Same rules. No edits... One post till clue.
It is easy, but I will make it $3 dollars for the weekend.
Have a look at this post count guessing contest:
http://www.talkgold.com/forum/r241073-.html
I am saying that multiple participants could win first prize, if they all could work as a team and coordinate their efforts. How?
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  #2  
Old 11-30-2008, 05:15 AM
fftrading fftrading is offline
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Default Re: $3 easy logical question.

just save all guessed numbers in excel file including the number of participants that guessed that number (it's good to write down their nick)
everyone can guess the same number --> all will guess the same number set that may include winning number
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  #3  
Old 11-30-2008, 05:25 AM
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Default Re: $3 easy logical question.

Quote:
Originally Posted by mrGSH
I am saying that multiple participants could win first prize, if they all could work as a team and coordinate their efforts. How?
Only takes 2 of you to do it....Contest started at 608,016 you can't make consecutive posts so you just take turns to post...
Person one posts the odd numbers(608,017...608,019)....And person 2 covers the even numbers(608,018...608,020)....

To increase your winnings go back and swap who does evens and who does odds...That way you both win $4

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  #4  
Old 11-30-2008, 05:34 AM
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Default Re: $3 easy logical question.

Both are close, but I meant MULTIPLE.... Lets simplify it. Lets say 10 participants.... How should they coordinate to all win $4? What about both, $4 and $2 for each?
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  #5  
Old 11-30-2008, 05:38 AM
fftrading fftrading is offline
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Default Re: $3 easy logical question.

guess the same number and save it in excel file.
About guessing,they should guess a chain of numbers
For example, they start at 608,016.
1st person post 608,017
2nd person post 608,017
.......
10th person post 608,017
1st person post 608,018
2nd person post 608,018
.......
10th person post 608,018
1st person post 608,019
2nd person post 608,019
.......
10th person post 608,019
continue

but I think they should start at 608,100
keep the record in excel file when posting number

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Old 11-30-2008, 05:44 AM
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Default Re: $3 easy logical question.

It is actually simpler, and no M$ products are needed. As a clue, let me remind that they ALL should coordinate....
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  #7  
Old 11-30-2008, 05:44 AM
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Default Re: $3 easy logical question.

Quote:
Originally Posted by mrGSH
Both are close, but I meant MULTIPLE.... Lets simplify it. Lets say 10 participants.... How should they coordinate to all win $4? What about both, $4 and $2 for each?
My method works with 2 participants or 10...or 1000....or as many as you want in the group....You just repeat the process of each person posting every number...
This way you will all have every number covered and you will all win the prize

You could also manipulate to a point the number of posts in the folder...
Naturally the less number of posts makes it less work to do...

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  #8  
Old 11-30-2008, 05:47 AM
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Default Re: $3 easy logical question.

Quote:
Originally Posted by fftrading
keep the record in excel file when posting number
Hint...Go one number after the other then you don't need excel shmexcel
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  #9  
Old 11-30-2008, 05:55 AM
fftrading fftrading is offline
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Default Re: $3 easy logical question.

Quote:
It is actually simpler, and no M$ products are needed. As a clue, let me remind that they ALL should coordinate....
so they just post the same numbers and continue with next number one by one (start at 608,016)

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  #10  
Old 11-30-2008, 05:55 AM
thebigone thebigone is offline
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Default Re: $3 easy logical question.

personally,i will monitor from the start of the time for 2 hours (can guess in 3hours time).after this two hours i will calculate the average post per minutes..then monitor for at least half an hours for deviation on the previous calculated average post.. make a slight adjusted, predict the the post count in about 6hours45minnutes..then make a plus(+) & minus(-) of about 100 post..started from there,more than half hours left will be enough for us to get the correct answer.. then it also take 2 person and do about the same thing like okosh mention..then swap back the odd and even..with this way,we can win the both correct 1st price and also both closest guess..

but this is wilt the condition..as mention "Anyone with the correct number will win "..if its not..we can still take exact and closest guess as a team of two..
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